Question

Find the x-and y-intercepts of the following equations.

2x + 3y = 12

Answer 1

X intercepts=-c/a=-(-12)/2=6
Y intercepts =-c/b=-(-12)/3=4

Answer 2

$<b>!...............UR ANSWER DEAR................!$


$\color{Red}{ \boxed{\bold{ \underline{ Solution }}}}$


✔ 2x + 3xy = 12

put the value of x = 0

2×0 + 3y = 12

3y = 12

3y/3 = 12/3

y = 4

Therefore, y-intercept = (0, 4)

Now , put the value of y = 0

2x + 3 × 0 = 12

2x = 12

2x/2 = 12/2

x = 6


Therefore, x-intercept = (6, 0)


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