find the x intercept of the curve y=2log (√(x-1)-2)
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Answer:
The x-intercept has the form (c,0) where c is a constant.
So, set y = 0:
0=2log(x−2)+10=2log(x−2)+1
⟹2log(x−2)=−1⟹2log(x−2)=−1
⟹log(x−2)=−12⟹log(x−2)=−12
Assuming that Assuming that
log(x−2)=loge(x−2)log(x−2)=loge(x−2)
then exponentiate to get: then exponentiate to get:
eloge(x−2)=e−12⟹eloge(x−2)=e−12⟹
x−2=e−12⟹x−2=e−12⟹
x=2+1e12⟹x=2+1e12⟹
x=2+1e√≈2.60653066x=2+1e≈2.60653066
by calculator. So the x-intercept is
(2+e−12,0)≈(2.60653066,0).(2+e−12,0)≈(2.60653066,0).
This answer holds because
x≈2.60653066⟹x−2=2.60653066=0.60653066>0.x≈2.60653066⟹x−2=2.60653066=0.60653066>0.
The argument of a logarithm cannot be negative in the real numbers. If it is, then the logarithm is undefined.
Step-by-step explanation:
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