Math, asked by prayagkulal7, 9 months ago

find the x
please anyone solve this​

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Answered by PURNA9239
38

Answer:

EXTERIOR ANGLE OF A TRIANGLE = THE SUM OPPOSITE INTERIOR ANGLES OF A TRIANGLE

a) x = 70° + 50° = 120°

b) x = 65° + 45° = 110°

c) x = 30° + 40° = 70°

d) x = 60° + 60° = 120°

e) x = 50° + 50° = 100°

f) x = 30° + 60° = 90°

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Answered by Anonymous
5

EXTERIOR ANGLE OF A TRIANGLE = THE SUM OPPOSITE INTERIOR ANGLES OF A TRIANGLE

a) x = 70° + 50° = 120°

b) x = 65° + 45° = 110°

c) x = 30° + 40° = 70°

d) x = 60° + 60° = 120°

e) x = 50° + 50° = 100°

f) x = 30° + 60° = 90°

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