find the x
please anyone solve this
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Answer:
EXTERIOR ANGLE OF A TRIANGLE = THE SUM OPPOSITE INTERIOR ANGLES OF A TRIANGLE
a) x = 70° + 50° = 120°
b) x = 65° + 45° = 110°
c) x = 30° + 40° = 70°
d) x = 60° + 60° = 120°
e) x = 50° + 50° = 100°
f) x = 30° + 60° = 90°
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Answered by
5
EXTERIOR ANGLE OF A TRIANGLE = THE SUM OPPOSITE INTERIOR ANGLES OF A TRIANGLE
a) x = 70° + 50° = 120°
b) x = 65° + 45° = 110°
c) x = 30° + 40° = 70°
d) x = 60° + 60° = 120°
e) x = 50° + 50° = 100°
f) x = 30° + 60° = 90°
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