Question

find the x value and please explain on the paper and keep photo ok please ​​

Answer 1

$\begin{gathered} {5}^{2x + 1} \div 25 = 125 \\ = > {5}^{2x + 1} \div {5}^{2} = 125 \\ = > {5}^{2x + 1 - 2} = {5}^{3} \end{gathered}$

Now, but equating the power we have,

=> 2x +1 - 2 = 3

=> 2x - 1 = 3

=> 2x = 3+1

=> 2x = 4

=> x = 4/2

=> x = 2

Hence, the value of x = 2.

Answer 2

Step-by-step explanation:

Given :-

5^(2x+1) ÷ 25 = 125

To find :-

Find the value of x ?

Solution :-

Given equation is 5^(2x+1) ÷ 25 = 125

25 = 5×5 = 5^2

125 = 5×5×5 = 5^3

It can be written as

=> 5^(2x+1)÷(5^2) = (5)^3

=> 5^(2x+1) / (5^2) = (5)^3

=> 5^(2x+1-2) = 5^3

Since , a^m / a^n = a^(m-n)

=> 5^(2x-1) = 5^3

We know that

If the bases are equal then exponents must be equal.

=> 2x-1 = 3

=> 2x = 3+1

=> 2x = 4

=> x = 4/2

=> x = 2

Therefore, x = 2

Answer:-

The value of x for the given problem is 2

Check:-

If x = 2 then LHS of the equation

=> 5^(2×2+1)÷(5^2)

=> 5^(4+1)÷(5^2)

=> (5^5)÷ (5)^2

=> 5^(5-2)

=> 5^3

=> 5×5×5

=> 125

=> RHS

LHS = RHS is true for x = 2

Used formulae:-

• a^m / a^n = a^(m-n)
• If the bases are equal then exponents must be equal.