find the x value and please solve on paper and keep photo please
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Step-by-step explanation:
Given :-
(8/9)^3 × (8/9)^-6 = (8/9)^(2x-1)
To find :-
Find the value of x ?
Solution :-
Given equation is (8/9)^3 × (8/9)^-6 = (8/9)^(2x-1)
=> (8/9)^(3-6) = (8/9)^(2x-1)
Since a^m × a^n = a^(m+n)
=> (8/9)^-3 = (8/9)^(2x-1)
We know that
If the bases are equal then exponents must be equal.
=> -3 = 2x-1
=> 2x-1 = -3
=> 2x = -3+1
=> 2x = -2
=> x = -2/2
=> x = -1
Answer:-
The value of x for the given problem is -1
Check:-
If x = -1 then
LHS = (8/9)^3 × (8/9)^-6
=>(8/9)^3-6
=> (8/9)^-3 ------(1)
RHS = (8/9)^(2×-1-1)
=> (8/9)^(-2-1)
=> (8/9)^-3-------(2)
LHS = RHS is true for x = -1
Used formulae:-
→ a^m × a^n = a^(m+n)
→If the bases are equal then exponents must be equal.
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