Question

find the x value if log2,log6,logx are in G.P​

Answer 1

G.p=log2,log6,logx

a=log2

Answer 2

The value of x is 7.47.

Step-by-step explanation:

Given : If $\log 2, \log 6, \log x$ are in G.P​.

To find : The value of x ?

Solution :

When three terms are in G.P a,b,c then $b^2=ac$.

Here, $\log 2, \log 6, \log x$ are in G.P​.

So, $a=\log 2, b=\log 6, c=\log x$

Substitute,

$(\log 6)^2=(\log 2)\times (\log x)$

$\log x=\frac{(\log 6)^2}{\log 2}$

$\log x=2.011$

Taking antilog,

$x=e^{2.011}$

$x=7.47$

Therefore, the value of x is 7.47.

#Learn more

If -5/5 , x/-5, -2/5 are in G.P then find the value of 'x'

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