find the x,y and z....
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hey
here's your answer !!
AB is || to CD.
now angle CQP and angle PQR sum up to 180 degree ( angle CQR )
So , angle CQP + angle PQR = angle CQR
=> 120 degree + angle PQR = 180 degree
=> angle PQR = 60 degree.
now, angle PQR and angle APQ are alternate angles
so , angle PQR = angle APQ.
so, x = 60 degree.
now angle DRP and angle QRP sum up to 180 degree ( angle CQR )
So , angle DRP + angle QRP = angle QRD
=> 115 degree + angle QRP = 180 degree
=> angle QRP = 65 degree.
now, angle QRP and angle BPR are alternate angles
so , angle QRP = angle BPR
so, z = 65 degree.
Now in triangle PQR ,
angle QRP + angle PQR + angle QPR = 180 degree
65 degree + 60 degree + x = 180 degree
=> 125 degree + x = 180 degree
=> x = 55 degree.
Hope it helps !!
here's your answer !!
AB is || to CD.
now angle CQP and angle PQR sum up to 180 degree ( angle CQR )
So , angle CQP + angle PQR = angle CQR
=> 120 degree + angle PQR = 180 degree
=> angle PQR = 60 degree.
now, angle PQR and angle APQ are alternate angles
so , angle PQR = angle APQ.
so, x = 60 degree.
now angle DRP and angle QRP sum up to 180 degree ( angle CQR )
So , angle DRP + angle QRP = angle QRD
=> 115 degree + angle QRP = 180 degree
=> angle QRP = 65 degree.
now, angle QRP and angle BPR are alternate angles
so , angle QRP = angle BPR
so, z = 65 degree.
Now in triangle PQR ,
angle QRP + angle PQR + angle QPR = 180 degree
65 degree + 60 degree + x = 180 degree
=> 125 degree + x = 180 degree
=> x = 55 degree.
Hope it helps !!
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