Question

find the xurrent in 20 ohm resistor using kvl and kcl​

Answer 1

Explanation:

Mesh 1:-2I

1

+2(I

1

+I

2

)=6v

⟹4I

1

−2I

2

=6v

⟹2I

1

−I

2

=3→(1)

Mesh 2:-4I

2

+2(I

1

+I

2

)=2v

⟹6I

2

−2I

1

=2→(2)

Equating (2) and (1)

I

2

=1A

I

1

=2A