Question

find the year when p is 1800 and a is 2178 and r is 10 percent p.a

Answer 1

$p = 1800 \\ a = 2178 \\ r = 10\%p.a. \\ intrest = a - p \\ int = 2178 - 1800 \\ int = 378 \\ t = \frac{int \times 100}{p \times r} \\ t = \frac{378 \times 100}{1800 \times 10} \\ t = 2.1$