find the "z" value......
9z^2-6z+1=0
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Given Equation is 9z^2 - 6z + 1 = 0
= > 9z^2 - 3z - 3z + 1 = 0
= > 3z(3z - 1) - (3z - 1) = 0
= > (3z - 1)(3z - 1) = 0
= > (3z - 1)^2 = 0
= > 3z = 1
= > z = (1/3)
Therefore the value of z = 1/3.
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siddhartharao77:
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