Question

Find the zeeos of the polynomial p(x)=2x^2-9

Answer 1

p(x) = 2x²-9

here zeros will be

2x²-9=0

=> (√2x)² - 3²=0

=> (√2x+3)(√2x-3)=0

=> x = 3/√2

Or

x = -3/√2

Answer 2

Answer:

zeroes of the polynomial are 3/_/2, -3_/2