Question

Find the zeores of polynomial √3ysquare+ 11y + 6 √ 3

Answer 1

√3y² + 11y + 6√3

= √3y²+9y+2y+6√3

= √3y(y+3√3)+2(y+3√3)

= (√3y+2)(y+3√3)

∴ y = -2/√3 or y = -3√3

Mark it as the brainliest plzzzzzzz.

Answer 2

Given:

Consider the given polynomial

$\sqrt{3}y^2+11y+6\sqrt{3}$

Find:

Zeroes of the polynomial

Solution:

$\sqrt{3}y^2+11y+6\sqrt{3}\\\\=\sqrt{3}y^2+9y+2y+6\sqrt{3}\\\\=\sqrt{3}y(y+3\sqrt{3})+2(y+3\sqrt{3})\\\\=(y+3\sqrt{3})(\sqrt{3}y+2)$

Now if

$\sqrt{3}y+2=0\\\\y=-\frac{2}{\sqrt{3}}$

and if

$(y+3\sqrt{3})=0\\\\y=-3\sqrt{3}$