Question

Find the zeores of quadratic polynomial x2 +7x+10 . verify it​

Answer 1

Answer:

given polynomial p(x)=x²+7x+10

we have to find the zeroes of the given polynomial.

we can find by factorisation method

for factorisation method we have to equalise the p(x) with '0'

i.e. => x²+7x+10 =0

=>x²+5x+2x+10=0

=>x(x+5)+2(x+5)=0

=>(x+5)(x+2)=0

then,(x+5)=0,(x+2)=0

x= -5,x= -2

there fore,the zeroes of the given quadratic polynomial are -5,-2.

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Answer 2

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

Hope it helps