Question

Find the zeores of qudratic polynomial 4y2-8y

Answer 1

Step-by-step explanation:

first we shall take it equals to 0

therefore, 4y^2-8y=0 and solve it

Answer 2

Step-by-step explanation:

• 4y²-8y
• 4y(y - 4)
• either 4y = 0

y = 0

• or y - 4 = 0

y = 4

therefore zeros of the polynomial are 0,4

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