find the zeors of the quadratic polynomial 6x^2-3-7x
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the zeroes of the polynomial are 3/2 and -1/3
Sachingeorge123:
6x^2+2x-9x-3
u can split the polynomial by factorisation
i donot know how to factorise edit ur answer and do it for me
now 2x(3x+1)-3(3x+1)=0
2x-3=0 and 3x+1=0
2x=3 and 3x=-1
so x=3/2 and x=-1/3
thanks
did u understood
yes
Answered by
1
one is -1/3and other is 3/2
it's happen by this way 6x^2-7x-3,6x^2-[9-2]x-3,6x^2-9x+2x-3,3x(2x-3)+1(2x-3),(3x+1)(2x-3),x=-1/3and x=3/2 This is the process of factorisation method
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