Question

find the zero es of the following quadratic polynomial
2x2-9-3x​

Answer 1

Answer:

3 and - 3/2

Step-by-step explanation:

Given quadratic polynomial ;

• 2x² - 9 - 3x

On rearranging the terms, we get -

• 2x² - 3x - 9

We can find zeroes by splitting the middle term. To split middle term, we need two numbers such that their sum is 3, and product is 18 (9 * 2 = 18).

Such two numbers can be (-6, 3).

Here we go ;

⇒ 2x² - 3x - 9 = 0

⇒ 2x² - 6x + 3x - 9 = 0

⇒ 2x(x - 3) + 3(x - 3) = 0

⇒ (x - 3)(2x + 3) = 0

⇒ x = 3 or x = - 3/2

Hence, the zeroes of the quadratic polynomial are 3 and - 3/2.

Answer 2

Answer:

3 and - 3/2

Step-by-step explanation:

Given quadratic polynomial ;

2x² - 9 - 3x

On rearranging the terms, we get -

2x² - 3x - 9

We can find zeroes by splitting the middle term. To split middle term, we need two numbers such that their sum is 3, and product is 18 (9 * 2 = 18).

Such two numbers can be (-6, 3).

Here we go ;

⇒ 2x² - 3x - 9 = 0

⇒ 2x² - 6x + 3x - 9 = 0

⇒ 2x(x - 3) + 3(x - 3) = 0

⇒ (x - 3)(2x + 3) = 0

⇒ x = 3 or x = - 3/2

Hence, the zeroes of the quadratic polynomial are 3 and - 3/2.

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