Question

find the zero es of x^2 - 3x - 4​

Answer 1

${x}^{2} –3x–4=0$

${x}^{2} +x−4x−4=0$

$x(x+1)−4(x+1)=0$

$(x+1)(x−4)=0$

$either \: x+1=0 \: or \: x−4=0$

$so \: x=−1 \: or \: x = 4</strong></p><p></p><p><strong>[tex]so \: x=−1 \: or \: x = 4$

MORE:

• In general; if P(x) is a polynomial in x and k is any real number, then the value of P(k) at x = k is denoted by P(k) is found by replacing x by k in P(x). For a polynomial P(x), real number k is said to be zero of polynomial P(x), if P(k) = 0. Therefore, 1 and 2 are the zeros of