find the zero of 2xsquare-3+5x verify the relationalship between the zeroes and co efficients
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Solution :
→ 2x² +5x -3 = 0
→ 2x² + 6x - x - 3 = 0
→ 2x ( x + 3) - 1 ( x + 3 ) = 0
→ ( 2x - 1 ) ( x + 3 ) = 0
→ α = 1/2
→ β = - 3
verification of relationalship between the zeroes and co efficients
α + β = - b/a
→ 1/2 - 3 = - 5/2
→ - 5/2 = - 5/2
αβ = c/a
→ 1/2 × ( - 3 ) = - 3/2
→ - 3/2 = - 3/2
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