Question

find the zero of 3x^2-1.​

Answer 1

Step-by-step explanation:

(1/3)^1/2 is your answer..

hope you got your answer

Answer 2

Answer:

here,

p(x) = 3x² -1

to find zeroes,

p(x) = 0

=> 3x² -1 = 0

=> 3x² = 1

= > x² = ⅓

=> x = ± √⅓ so,

$x = \frac{1}{ \sqrt{3} } \\ or \\ x = \frac{ - 1}{ \sqrt{3} }$