Find the zero of 3x²+10x+7⅓
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Step-by-step explanation:
f(x)=√3x²+10x+7√3
=√3x²+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3)(√3x+7)
so,-√3 and -7/√3 are the zeros of the given polynomial.
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