Question

find the zero of 5xsq-4-8x=0

Answer 1

$hii... \\ 5 {x}^{2} - \: 8x \: - 4 = 0 \\ 5 {x}^{2} - \: 10x \: + \: 2x \: - 4 \: = \: 0 \\ 5x(x - 2) \: + \: 2(x - 2) = 0 \\ (x - 2) \: (5x + 2) = 0 \\ so.. \\ (x - 2) = 0 \: and \: (5x + 2) = 0 \\ x = 2 \: and \: 5x = - 2 = > x = \frac{ - 2}{5} \\ \\ hope \: this \: helps$

Answer 2

Step-by-step explanation:

see The attachment

Mate...!!!✌️