find the zero of 6x^2-7x-3
Answers
Answered by
6
here is your answer my friend i hope this will help you
Attachments:
Answered by
6
Hey Friend.... Here's ur solution....
=> 6x²-7x-3
=> 6x²-9x+2x-3
=> 3x(2x-3) +1(2x-3)
=> (2x-3)(3x+1)
=> Either 2x-3=0 Or 3x+1=0
Hence the value of x= 3/2.
I hope it is clear to you...
=> 6x²-7x-3
=> 6x²-9x+2x-3
=> 3x(2x-3) +1(2x-3)
=> (2x-3)(3x+1)
=> Either 2x-3=0 Or 3x+1=0
Hence the value of x= 3/2.
I hope it is clear to you...
Garima4121:
mark as brainliest plz..
Similar questions