Find the zero of 7y2-11/3y-2/3
Answers
Answered by
0
Step-by-step explanation:
7y²-11/3y-2/3 = 0
×3
21y²-11y-2 =0
y = [-b±(√b²-4ac)] / 2a
here, a= 21 b= -11 , c= -2
y= [ 11± √ 121-4(21)(-2) ]/2(21)
=[11 ± (√121+168)] / 42
= 11± √289 / 42
= 11±17/42
y = (11+17)/42. y= (11-17)/42
y = 28/42. y = (-6)/42
y = 2/3. y = -1/7
Attachments:

Similar questions
English,
2 months ago
English,
2 months ago
Social Sciences,
2 months ago
English,
4 months ago
History,
4 months ago
Math,
1 year ago
Accountancy,
1 year ago