Question

Find the zero of 7y2-11/3y-2/3

Answer 1

Step-by-step explanation:

7y²-11/3y-2/3 = 0

×3

21y²-11y-2 =0

y = [-b±(√b²-4ac)] / 2a

here, a= 21 b= -11 , c= -2

y= [ 11± √ 121-4(21)(-2) ]/2(21)

=[11 ± (√121+168)] / 42

= 11± √289 / 42

= 11±17/42

y = (11+17)/42. y= (11-17)/42

y = 28/42. y = (-6)/42

y = 2/3. y = -1/7