Question

find the zero of f(x) =x3-3px2+qx-r​

Answer 1

Step-by-step explanation:

f(x)=x3-3px2+qx-r

If x=1;put x place 1;

f(1)=1×3-3p×1×2+q×1-r

=3-6p+q-r

we want the values of p,q,r then I do the easy.

you know the values of p,q,r then you put the value in place of p,q,r.

For example:you see this

p=1,q=2,r=3;then

=3-6p+q-r

=3-6×1+2-3

=3-6-1

=3-7

= -4

Do like this method