Find the zero of g(x)=6x^2-3
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Solution:
Given g(x) = 6x²-3
Let g(x) = 0
=> 6x²-3 = 0
=> 6x² = 3
=> x² = 3/6
=> x² = 1/2
=> x = ±1/√2
Therefore,
-1/√2 , 1/√2 are zeroes
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