Question

find the zero of given quadratic polynomial (i)6x²-3-7x​

Answer 1

Answer:

6x²-3-7x

Or 6x²-7x-3 =0

6x²-9x+2x- 3 =0

3x(2x- 3) + 1(2x- 3)=0

(3x +1) (2x-3) =0

x = -1/3, x = 3/2

Step-by-step explanation:

I hope it helps you !

Answer 2

=6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1)

⇒2x-3=0 or ⇒3x+1=0

⇒x=3/2 or ⇒ x= - 1/3

α=3/2 ,β= - 1/3

⇒α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

⇒αβ=c/a

⇒ 3/2(-1/-(1/3)

=>-1/2= -7/6

=>1/2=7/6