Question

find the zero of P(x)=(x+3)²-x²​

Answer 1

Answer:

(x+3)²-x²

by using formula (a+b)²=a²+2ab+b²

x²+2×x×3+(3)²-x²=0

x²+6x+9-x²=0

x²-x²+6x +9 =0

6x+9=0

3(2x+3)=0

2x+3 =0

2x =-3

x= -3/2