Question

find the zero of p (x)=(x-3)(x+2)

Answer 1

hello friend

p(x) = (x-3)(x+2)
put the quadratic equation =0

since u have to find the zeros
you will get either x= 3 or -2
so zeros are 3,-2.

Answer 2

P(x)=(x-3)(x+2)
Equate the equation ro zero to find zeroes/roots of the equation
We get x=3, -2 which are zeroes/roots of the equation