Question

find the zero of p(x)= x2+24x+145 ÷ x+10​

Answer 1

Step-by-step explanation:

p(x) = x^2 + 24 + 145

g(x) = x + 10

Let, g(x) = 0

=> x + 10 = 0

=> x = -10

Remainder of p(x)

p(x) = x^2 + 24+ 145

=> p(-10) = (-10)^2 + 24 + 145

= 100 + 24 + 145

= 124 + 145

= 269