Question

find the zero of p(x) =x2-2x-3​

Answer 1

Answer:

-1,3

Step-by-step explanation:

By factorisation method

${x}^{2} - 2x - 3 = 0$

${x}^{2} - 3x + x - 3 = 0$

${x}(x - 3) + 1(x - 3) = 0$

$(x + 1)(x - 3) = 0$

$x + 1 = 0 \: \: \: \: \: or \: \: \: \: x - 3 = 0$

$x = - 1 \: \: \: \: or \: \: \: \: x = 3$

Hence, -1 and 3 are the roots of quadratic equation.

Answer 2

Answer:

-3 is the answer hope it may help you