Question

find the zero of p(x)=xsquare+3x-4​

Answer 1

Answer:

(x-1)

Step-by-step explanation:

the zero of polynomial p(x)=x^2+3x-4 is (x-1)

first we will equate x-1 =0

x=1

then put the value of 1 in:

p(1)=(1)^2+3×1-4

p(1)=1+3-4

p(1)=4-4

p(1)=0

hence x-1 is the zero of the polynomial:

p(x)=x^2+3x-4

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