Question

find the zero of poliyonomial
${2x }^{2} + 7x - 4$
​

Answer 1

Answer:

$\large{\sf\purple{ \implies}x = \frac{1}{2} \: \: or \: \: x = - 4}</p><p>$

Step-by-step explanation:

$\sf\purple{ {2x}^{2} + 7x - 4 = 0} \\ \\ \sf\purple{ \implies \: {2x}^{2} + 8x - x - 4 = 0} \\ \\ \sf\purple{ \implies \: 2x(x + 4) - 1(x + 4) = 0} \\ \\ \sf\purple{ \implies \: (2x - 1)(x + 4) = 0} \\ \\ \bf{now \: \red{2x - 1 = 0 \: or \: x + 4 = 0}} \\ \\ \sf\purple{ \implies}x = \frac{1}{2} \: \: or \: \: x = - 4</p><p>$

Answer 2

Using  $\frac{-b+-\sqrt^{b^{2}-4ac } }{2a}$

a=2

b=7

c=(-4)

Zeros:-

Substitute the values you will get the answer