Question

find the zero of polynomial 25 x square + 5 x and find the coefficient and the zero relationship​

Answer 1

Zeroes are 0 and

Step-by-step explanation:

Given: Quadratic Polynomial , 25x² + 5x

To find: Zeroes of Polynomial and Verify the relation between zeroes and coefficient

To find zeroes we equate polynomial with 0

⇒ 25x² + 5x = 0

5x ( 5x + 1 ) = 0

5x = 0  and 5x + 1 = 0

x = 0   and  x =

Therefore, Zeroes are 0 and

let, α = 0 and β =

first relation is sum of zeroes/roots =

LHS = α + β =

RHS = [tex\frac{-b}{a}=\frac{-5}{25}=\frac{-1}{5}[/tex]

LHS = RHS

Hence Verified

Second Relation is Product of zeroes/roots =

LHS = αβ =

RHS = [tex\frac{c}{a}=\frac{0}{25}=0[/tex]

LHS = RHS

Hence Verified

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