Question

find the zero of polynomial 2x^2+7x-4 is_ a) 2 b)1/2 c)-1/2 d)-2​

Answer 1

2x² + 7x - 4

2x² - x + 8x - 4

x(2x - 1) + 4(2x - 1)

(x + 4) (2x - 1) are factors of the given polynomial

For zeroes

x+4=0

x = -4

2x-1=0

x = ½

Hence, the zeroes are -4 and 1/2.

Mark me brainliest

Answer 2

Answer:

b) 1/2

Step-by-step explanation:

2x² + 7x - 4 = 0

⇒ 2x² - x + 8x - 4 = 0

⇒ (2x² - x) + (8x - 4) = 0

⇒x(2x - 1) + 4(2x - 1) = 0

⇒ (2x - 1)(x + 4) = 0

⇒ x = 1/2 or x = -4

Hence, the correct option is b) 1/2

More things to know:-

• (a + b)² = a² + 2ab + b²

• (a - b)² = a² - 2ab + b²

• a² - b² = (a + b)(a - b)

• (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2 ca

                          = a² + b² + c² + 2(ab + bc + ca)  

• (a + b)³ = a³ + b³ + 3ab(a + b)

                    =  a³ + b³ + 3a²b + 3ab²  

• (a - b)³ = a³ - b³ - 3ab(a - b)                    

                   = a³ - b³ - 3a²b + 3ab²    

• a³ + b³ = (a + b)(a² - ab + b²)

• a³ - b³ = (a - b)(a² + ab + b²)

• a³+b³ +c³- 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)

• (x + p)(x + q) = x² + (p + q)x + pq

I hope that this helped

Mark my answer as the brainliest and follow me