find the zero of polynomial 2x³ +3x²-11x-6
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2x³ + 3x² - 11x - 6
= 2x³ - 4x² + 7x² - 14x + 3x - 6
= 2x²(x -2) + 7x(x -2) + 3(x -2)
= {2x² + 7x +3}(x -2)
= {2x² + 6x + x + 3}(x -2)
={2x(x +3) + 1(x +3) }(x -2)
= (2x +1)(x +3)(x -2)
hence, zeros of polynomial are , -1/2 , -3 and 2
= 2x³ - 4x² + 7x² - 14x + 3x - 6
= 2x²(x -2) + 7x(x -2) + 3(x -2)
= {2x² + 7x +3}(x -2)
= {2x² + 6x + x + 3}(x -2)
={2x(x +3) + 1(x +3) }(x -2)
= (2x +1)(x +3)(x -2)
hence, zeros of polynomial are , -1/2 , -3 and 2
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Hi see this PIC for your answer .
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