Find the zero of polynomial 3x2 - 1 1x -34 and verify the relationship between zero and coefficient of Polynomial.
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Step-by-step explanation:
We have,
p(x)=3x 3 −5x 2 −11x−3
And the zeros are
3,−1,
3−1
Verifying the zeros,
x=3,p(3)=3(3)
3
−5(3)
2
−11(3)−3
=81−45−33−3
=0
=x−1,p(−1)=3(−1)
3
−5(−1)
2
−11(−1)−3
=−3−5+11−3
=0
x= 3−1,p( 3−1 )=3( 3−1 )
3 −5( 3−1 ) 2 −11( 3−1 )−39−1 − 95
+ 311 −39−1−5−33−27
0
Now verifying the relation between zeros and coefficients is:
for,
p(x)=3x
3 −5x 2 −11x−3
a=3,b=−1,c=−11,d=−1
and zeros α=3,β=−1γ= 3−1
Now,
α+β+γ
=3+(−1)+ 3−1
= 39−3−1
35 = a−b
αβ+βγ+γα
=(3)(−1)+(−1)( 3−1 )+( 3−1 )(3)3−9+1−3
= 3−11 = ac
αβγ
=(3)(−1)( 3−1 )
1= ad
✪============♡============✿
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