Math, asked by 62555, 1 month ago

Find the zero of polynomial 3x2 - 1 1x -34 and verify the relationship between zero and coefficient of Polynomial. ​

Answers

Answered by MizBroken
9

Step-by-step explanation:

We have,

p(x)=3x 3 −5x 2 −11x−3

And the zeros are

3,−1,

3−1

Verifying the zeros,

x=3,p(3)=3(3)

3

−5(3)

2

−11(3)−3

=81−45−33−3

=0

=x−1,p(−1)=3(−1)

3

−5(−1)

2

−11(−1)−3

=−3−5+11−3

=0

x= 3−1,p( 3−1 )=3( 3−1 )

3 −5( 3−1 ) 2 −11( 3−1 )−39−1 − 95

+ 311 −39−1−5−33−27

0

Now verifying the relation between zeros and coefficients is:

for,

p(x)=3x

3 −5x 2 −11x−3

a=3,b=−1,c=−11,d=−1

and zeros α=3,β=−1γ= 3−1

Now,

α+β+γ

=3+(−1)+ 3−1

= 39−3−1

35 = a−b

αβ+βγ+γα

=(3)(−1)+(−1)( 3−1 )+( 3−1 )(3)3−9+1−3

= 3−11 = ac

αβγ

=(3)(−1)( 3−1 )

1= ad

✪============♡============✿

 \huge \pink{✿} \red {C} \green {u} \blue {t} \orange {e}  \pink {/} \red {Q} \blue {u} \pink {e} \red {e} \green {n} \pink {♡}

Similar questions