Find the zero of polynomial
4√5 – 24x
9√5 and the
relations between the
the coefficents of polynomials
Answers
Step-by-step explanation:
Given -
- p(x) = 4√5x² - 24x - 9√5
To Find -
- Zeroes of the polynomial
- Verify the relationship between the zeroes and the coefficient
Now,
→ 4√5x² - 24x - 9√5
Here,
a = 4√5
b = -24
c = -9√5
By using quadratic formula :-
- → x = -b ± √b² - 4ac/2a
→ -(-24) ± √(-24)² - 4×4√5×-9√5/2(4√5)
→ 24 ± √576 + 720/8√5
→ 24 ± √1296/8√5
→ 24 ± 36/8√5
Zeroes are -
x = 24 + 36/8√5
→ 60/8√5
→ 15/2√5
And
x = 24 - 36/8√5
→ -12/8√5
→ -3/2√5
Verification :-
- α + β = -b/a
→ 15/2√5 + (-3/2√5) = -(-24)/4√5
→ 15 - 3/2√5 = 24/4√5
→ 12/2√5 = 6/√5
→ 6/√5 = 6/√5
LHS = RHS
And
- αβ = c/a
→ 15/2√5 × -3/2√5 = -9√5/4√5
→ -45/20 = -9/4
→ -9/4 = -9/4
LHS = RHS
Hence,
Verified...
It shows that our answer is absolutely correct.
15/2√5
-3/2√5
- p(x) => 4√5 – 24x 9√5
- zeros of the polynomial.
- verify the relationship between the zeros of the coefficient.
Now,
4√5 – 24x 9√5
a = 4√5
b = -24
c = -9√5
By using quadratic formula:
x = -b +,- √b² - 4ac/2a
-(-24) -,+ √(-24)² - 4 × 4√5 × (-9√5/2)(4√5)
24 -,+ √576 + 720/8√5
24 +,- √1296/8√5
24 +,- 36/8√5
x = 24 + 36/8√5
60/8√5
15/2√5
x = 24 + 36/8√5
-12/8√5
-3/2√5
- β + α = -b/a
15/2√5 + (-3/2√5) = -(-24)/4√5
15 - 3/2√5 = 24/4√5
12/2√5 = 6/√5
6/√5 = 6/√5
- βα = c/a
15/2√5 × -3/2√5 = -9√5/4√5
-45/20 = -9/4
-9/4 = -9/4