find the zero of polynomial 5x^2-3-2x
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HEY USER HERE IS YOUR ANSWER:-
5x^2 - 2x - 3
5x^2 - 5x + 3x - 3
5x ( x - 1 ) + 3 ( x - 1 )
( 5x + 3 ) ( x - 1 )
or
x = -3/5 , x = 1
( Negative value rejected and positive will be taken as real value of x i.e 1 )
HOPE IT HELPS YOU !!!!!.........✌️✌️✌️
5x^2 - 2x - 3
5x^2 - 5x + 3x - 3
5x ( x - 1 ) + 3 ( x - 1 )
( 5x + 3 ) ( x - 1 )
or
x = -3/5 , x = 1
( Negative value rejected and positive will be taken as real value of x i.e 1 )
HOPE IT HELPS YOU !!!!!.........✌️✌️✌️
Answered by
0
Hey mate ☺️
See the attachment ☺️
Hope it helps you ☺️✌️✌️
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