Question

Find the zero of polynomial (a) p(x) = (x-2)^2 - (x+2)^2

Answer 1

Answer:

Step-by-step explanation:

P(x) =(x-2)^2-(x+2)^2

Using identity (a+b) ^2=a^2+2ab+b^2 we get

P(x) =x^2-4x+4 - (x^2+4x+4)

P(x) =x^2-4x+4-x^2-4x-4

P(x) =-8x

Therefore p(x) =8x

If p(x) =0

8x=0

Or x=0

Answer 2

Step-by-step explanation:

Given:

p(x) = (x - 2)² - (x + 2)²

To find:

zeroes of the polynomial.

Solution:

We have

p(x) = (x - 2)² - (x + 2)²

Finding a zero of the polynomial, is the same as solving the equation p(x) = 0, we get

(x - 2 + x + 2)(x - 2 - x - 2) = 0

⇒ (2x) (-4) = 0

⇒-8x = 0

⇒x = 0

Hence, 0 is a zero of the polynomial p(x) = (x - 2)² - (x + 2)²