Question

find the zero of polynomial p(x)=2x³+3x²-18x-27.​

Answer 1

Step by step solution :

STEP

1

:

Equation at the end of step 1

 (((2 • (x3)) +  3x2) -  18x) -  27  = 0  

STEP  

2

:

Equation at the end of step

2

:

 ((2x3 +  3x2) -  18x) -  27  = 0  

STEP

3

:

Checking for a perfect cube

3.1    2x3+3x2-18x-27  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3+3x2-18x-27  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -18x-27  

Group 2:  2x3+3x2  

Pull out from each group separately :

Group 1:   (2x+3) • (-9)

Group 2:   (2x+3) • (x2)

              -------------------

Add up the two groups :

              (2x+3)  •  (x2-9)