Find the zero of polynomial: p(x)=(x+1)(x+2)
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Answer:
2 is the zeroes of a polynomial p(x)=(x+1)(x+2)
Step-by-step explanation:
let p(x)=0
so , x= 0(putting 0 in the position of x)
Solution= p(0)=(0+1)(0+2)
=p(0) = 1×2
= 2..
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