Find the zero of polynomial
P(x) = (x+2) (x+3)
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Answered by
16
(x+2) (x+3) = 0
x+2 = 0 or x+3 =0
x = -2 or x = -3
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Answered by
4
Answer:
x(x+3) 2(x+3)
x^2+3x+2x+6
x^2+5x+6
Let x be 0
p(x) = x^2+5x+6
p(0) = (0)^2+5(0)+6
p(0) = 0+0+6
p(0) = 6
Therefore, 6 is the zero of the given polynomial/p(x)
Step-by-step explanation:
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