Question

find the zero of polynomial p (x)=x(x-2)(x+3)

Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{x=0,2\:and\:-3}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

>>This is cubic polynomial bcz x has three degree of polynomial.

${x}^{ 3} + {x}^{2} - 6x = 0 \\ so \: its \: roots \: are \: \\ = ) x(x - 2)(x + 3) = 0\\ = )x = 0 \\ = ) x - 2 = 0 \\ = ) x = 2 \\ = ) x + 3 = 0 \\ = )x = - 3 \\ zeroes \: of \: this \: eqn \:0, \: 2 \: and \: - 3$

$\huge{\boxed{\boxed{\sf{x=0,2\:and\:-3}}}}$

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Answer 2

Answer:-

The above equation is a cubic polynomial.

$\bold{ {x}^{3} + {x}^{2} - 6x = 0}$

$\bold{x(x - 2)(x + 3) = 0}$

$\bold{x = 0 \: ,x - 2 = 0 \: ,x + 3 = 0}$

$\bold{x = 0 \:,x = 2 \:,x = - 3}$

$\mathfrak{Answer :- \: 0,2 \: and \: - 3}$