Question

find the zero of polynomial x^+5x+6​

Answer 1

Step-by-step explanation:

answer is in the attachment

hope it wil be helpful

Answer 2

Your Polynomial is:↓

${x}^{2} + 5x + 6$

Here, a = 1, b = 5, c = 6

So, zeroes are:

$\frac{ - b \: ± \: \sqrt{( {b}^{2} - 4ac)} }{2a} = \frac{- 5 \: ± \: \sqrt{ {5}^{2} - 4(1)(6) } }{2(1)} \\ = \frac{- 5 \: ± \: \sqrt{25 - 24} }{2} = \frac{ - 5\:± \: 1}{2}$

$α = \frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ β = \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$

Hope It Helps :)

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