Question

find the zero of quadratic polinomial x²-2x-8​

Answer 1

Answer:

-2, 4

Step-by-step explanation:

${x}^{2} + 2x - 4x - 8$

$x(x + 2) - 4(x + 2) = 0$

$(x + 2)(x - 4) = 0$

x = -2

x = 4

PLEASE MARK IT AS BRAINLIEST

Answer 2

Step-by-step explanation:

to find zeroes put

p(x) =0

${x}^{2} - 2x - 8 = 0 \\ factorize \: by \: spilttng \: the \: middle \: term - \\ \\ {x}^{2} - 4x + 2x - 8 = 0 \\ \\ x(x - 4) + 2(x - 4) = 0 \\ \\ (x - 4)(x + 2) = 0 \\ x = 4 \: and \: - 2 \: are \: the \: zeroes \: of \: the \: p(x).$