Question

find the zero of quadratic tsquare-15

Answer 1

Heya!

Here is yr answer.....


=> t² - 2t - 15

=> t² - 5t + 3t - 15

=> t(t-5) + 3(t-5)

=> (t-5) (t+3)


Hope it hlpz..

Answer 2

Solution :

${t}^{2} - 15 \\ = {t}^{2} - { \sqrt{15} }^{2} \\ = (t + \sqrt{15} )(t - \sqrt{15} ) \\ so \: t + \sqrt{15} = 0 \: and \: t - \sqrt{15} = 0 \\ = > t = - \sqrt{15} and \: t = \sqrt{15}$
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Hope it helps

#Amrit⭐