Question

find the zero of
$x^{2}$
-9

Answer 1

${x }^{2} - 9 \\ using \: {a}^{2} - {b}^{2} = (a + b)(a - b) \\ (x + 3)(x - 3) \\ zeroes \: are \: x = 3 \: and \: x = - 3$