Question

find the zero of the following and verify the relation between zero and Coefficient question is 4 x square + 8 x​

Answer 1

Question

p(x) = 4x^2 + 8x

a = 4

b = 8

c = 0

To find the zeros:

p(x) = 0

4x^2 + 8x = 0

4x(x+2) = 0

4x = 0 ; x+2 = 0

x = 0/4 = 0

x = -2

So, Zeros of p(x) are 0 and -2

Verifying the relation between Zeros and Coefficient

Sum of zeroes = 0 + (-2) = -2

Product of zeroes = 0 × (-2) = 0

Sum of zeroes = $\dfrac {-Coefficient\;of\ ; x}{Coefficient \;of\; x^2}$

= -b/a

= -8/4

= -2

Product of zeroes = $\dfrac {Constant\;term}{Coefficient\;of\;x^2}$

= c/a

=0/4

= 0

Hence, Verified.

Answer 2

Answer:

Question

p(x) = 4x^2 + 8x

a = 4

b = 8

c = 0

To find the zeros:

p(x) = 0

4x^2 + 8x = 0

4x(x+2) = 0

4x = 0 ; x+2 = 0

x = 0/4 = 0

x = -2

So, Zeros of p(x) are 0 and -2

Verifying the relation between Zeros and Coefficient

Sum of zeroes = 0 + (-2) = -2

Product of zeroes = 0 × (-2) = 0

$sum \: of \: zeros \: \dfrac {-Coefficient\;of\ ; x}{Coefficient \;of\; x^2} </p><p>Coefficientofx </p><p>2</p><p> </p><p>−Coefficientof ;x$

= -b/a

= -8/4

= -2

product of zeros =

$\frac{Coefficientofx </p><p>2}{</p><p> </p><p>Constantterm }$

= c/a

=0/4

= 0

Hence, Verified.