Find the zero of the following polynomial
1) p(x)=3x+5
2)p(y)=y^2+64
3)p(x)=3x^2-5
4)p(x)=7x-10
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Answer:
1) 3x+5=0
x=-5/3
2) y2+64=0
y2=64
y=8
3) 3x2-5=0
3x2=5
x2=5/3
4) 7x-10=0
7x=10
x=10/7
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