Question

find the zero of the following polynomial........ a) x^3-x​

Answer 1

Answer:

x = 1 or x = -1 or x = 0.

Step-by-step explanation:

Given :

$\large p(x)=x^3-x$

We have to find zeroes of p ( x )

$\large p(x)=x^3-x\\\\\\\large p(x)=x^3-x=0$

Taking x as common we have

$\large p(x)=x(x^2-1)=0$

Now comparing to zero we get

x = 0

or

$\large (x^2-1)=0\\\\\\\large x^2=1\\\\\\\large x=\sqrt1\\\\\\\large x=\pm1$

So we have x = 1 or x = -1

Thus we get all zeroes of polynomial x = 1 or x = -1 or x = 0.